Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 19

Answer

$\frac{\sqrt 5}{5}$

Work Step by Step

Let $cos^{-1}\frac{3}{5}=t$, we have $cos(t)=\frac{3}{5}$ and $sin\frac{t}{2}=\sqrt {\frac{1-cos(t)}{2}}=\sqrt {\frac{1-3/5}{2}}=\frac{\sqrt 5}{5}$
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