Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 23

Answer

$ \frac{\sqrt 6}{2}$

Work Step by Step

$sin75^\circ +sin15^\circ=2sin(\frac{75^\circ +15^\circ}{2})cos(\frac{75^\circ -15^\circ}{2})=2sin(45^\circ)cos(30^\circ)=2(\frac{\sqrt 2}{2})(\frac{\sqrt 3}{2}) =\frac{\sqrt 6}{2}$
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