Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 26

Answer

$0,1.911,\pi,4.373$

Work Step by Step

1. $-3cos(\frac{\pi}{2}-\theta)=tan\theta\Longrightarrow -3sin(\theta)=\frac{sin\theta}{cos\theta}\Longrightarrow sin(\theta)=0\ or\ cos\theta-=\frac{1}{3}$ 2. For $sin\theta=0$, we have $\theta=k\pi$ 3. For $cos\theta-=\frac{1}{3}$, we have $\theta=2k\pi+1.911$ or $\theta=2k\pi+4.373$ 4. Within $[0,2\pi)$, we have $\theta=0,1.911,\pi,4.373$
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