Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 28

Answer

$0.285,3.427$

Work Step by Step

1. $sin(\theta+1)= cos\theta\Longrightarrow sin\theta cos1+cos\theta sin1-cos\theta=0\Longrightarrow tan(\theta)=\frac{1-sin1}{cos1}$ 2. For $tan(\theta)=\frac{1-sin1}{cos1}\approx0.2934$, we have $\theta\approx k\pi+0.285$ 3. Within $[0,2\pi)$, we have $\theta=0.285,3.427$
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