Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 84

Answer

$ -\frac{\sqrt 3}{2}$

Work Step by Step

$-3sin^{-1}(x)=\pi\Longrightarrow sin^{-1}(x)=-\frac{\pi}{3}$, thus $x=-\frac{\sqrt 3}{2}$
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