Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 51

Answer

$\sqrt 2-1$

Work Step by Step

$tan\frac{\pi}{8}=tan\frac{\pi/4}{2}=\frac{1-cos\pi/4}{sin\pi/4} =\frac{1-\sqrt 2/2}{\sqrt 2/2}=\sqrt 2-1$
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