Answer
$-\frac{24}{25}$
Work Step by Step
1. Let $cos^{-1}(-\frac{3}{5})=t$ (t in quadrant II), we have $cos(t)=-\frac{3}{5}$ and $sin(t)=\frac{4}{5}$
2. Thus $sin(2t)=2sin(t)cos(t)=2(\frac{4}{5})(-\frac{3}{5})=-\frac{24}{25}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 62
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