Answer
$0,\frac{\pi}{2},\pi,\frac{3\pi}{2}$
Work Step by Step
1. $tan(2\theta)=0$, we have $2\theta=k\pi$ and $\theta=\frac{k\pi}{2}$
2. Within $[0,2\pi)$, we have $\theta=0,\frac{\pi}{2},\pi,\frac{3\pi}{2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 67
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