Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 50

Answer

$ \frac{1}{2}$

Work Step by Step

$sin70^\circ cos40^\circ-cos70^\circ sin40^\circ=sin(70-40)^\circ =sin(30)^\circ=\frac{1}{2}$
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