Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 58

Answer

$\frac{4+3\sqrt 3}{10}$

Work Step by Step

1. Let $sin^{-1}\frac{3}{5}=u$, we have $sin(u)=\frac{3}{5}$ and $cos(u)=\frac{4}{5}$ 2. Let $cos^{-1}\frac{1}{2}=v$, we have $cos(v)=\frac{1}{2}$ and $sin(v)=\frac{\sqrt 3}{2}$ 3. Thus $cos(u-v)=cos(u)cos(v)+sin(u)sin(v)=(\frac{4}{5})(\frac{1}{2})+(\frac{3}{5})(\frac{\sqrt 3}{2})=\frac{4+3\sqrt 3}{10}$
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