Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 79

Answer

$1.23$

Work Step by Step

We know that $\sec {a}=\dfrac{1}{\cos{(a)}}$. This can also be written as: $\sec^{-1} {a}=\cos^{-1} (\dfrac{1}{a})$ In order to get the answer in radians, we want to set the calculator in radians mode, and use the inverse cosine function (round off the result to two decimal places) to obtain: $\sec^{-1} (3) =\cos^{-1} (\dfrac{1}{3})=1.2310 \approx 1.23$ The equation $cos\theta=\frac{1}{3}$ implies that that $\theta$ lies in quadrant I and the angle of the final answer also lies in quadrant I, so we do not need to modify the result.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.