Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 65

Answer

$\frac{2\pi}{3},\frac{5\pi}{3}$

Work Step by Step

1. $tan\theta=-\sqrt 3$, we have $\theta=k\pi+\frac{2\pi}{3}$ 2. Within $[0,2\pi)$, we have $\theta=\frac{2\pi}{3},\frac{5\pi}{3}$
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