Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 528: 66

Answer

$\frac{3\pi}{4},\frac{7\pi}{4}$

Work Step by Step

1. $sin(2\theta)=-1$, we have $2\theta=2k\pi+\frac{3\pi}{2}$ and $\theta=k\pi+\frac{3\pi}{4}$ 2. Within $[0,2\pi)$, we have $\theta=\frac{3\pi}{4},\frac{7\pi}{4}$
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