Answer
(a) See graph.
(b) $3\pm\sqrt 2$
(c) See graph.
Work Step by Step
(a) To obtain the graph of $y=-3(x-3)^2+6$ from $y=x^2$, shift the curve 3 units to the right, stretch vertically by a factor of 3, reflect across the x-axis, then shift 6 units up. See graph.
(b) We can find the real zeros $x=3\pm\sqrt 2$
(c) See graph.
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