Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 91

Answer

(a) See graph. (b) $3\pm\sqrt 2$ (c) See graph.

Work Step by Step

(a) To obtain the graph of $y=-3(x-3)^2+6$ from $y=x^2$, shift the curve 3 units to the right, stretch vertically by a factor of 3, reflect across the x-axis, then shift 6 units up. See graph. (b) We can find the real zeros $x=3\pm\sqrt 2$ (c) See graph.
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