Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Zeros: $\dfrac{3}{2}$ $x$-intercept: $\dfrac{3}{2}$
To find the zeros of a function $g$, solve the equation $g(x)=0$ The zeros of the function are also the $x-$intercepts. Let $G(x)=0$: $$4x^2+9-12x=0$$ Rearranging the Equation: $$4x^2-12x+9$$ By Factoring: $$(2x-3)(2x-3)=0$$ Use the Zero-Product Property by equating each unique factor to zero to obtain: $2x-3 = 0$ $2x = 3$ $x=\dfrac{3}{2}$