Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 77


Zero: $\dfrac{1}{4}$ $x$-intercept: $\dfrac{1}{4}$

Work Step by Step

To find the zeros of a function $f$, solve the equation $f(x)=0$ The zeros of the function are also the $x-$intercepts. Let $g(x)=0$: $$16x^2-8x+1=0$$ By Factoring $$(4x-1)^2=0$$ $$ 4x-1 =0$$ $$4x=1$$ $$x=\dfrac{1}{4}$$ Thus, the zero, which is also the $x$-intercept, is $\dfrac{1}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.