## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Zero: $\dfrac{1}{4}$ $x$-intercept: $\dfrac{1}{4}$
To find the zeros of a function $f$, solve the equation $f(x)=0$ The zeros of the function are also the $x-$intercepts. Let $g(x)=0$: $$16x^2-8x+1=0$$ By Factoring $$(4x-1)^2=0$$ $$4x-1 =0$$ $$4x=1$$ $$x=\dfrac{1}{4}$$ Thus, the zero, which is also the $x$-intercept, is $\dfrac{1}{4}$