## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Zeros: $\dfrac{4}{5}$ $x$-intercepts: $\dfrac{4}{5}$
To find the zeros of a function $g$, solve the equation $g(x)=0$ The zeros of the function are also the $x-$intercepts. Let $F(x)=0$: $$25x^2+16-40x=0$$ Rearranging the Equation: $$25x^2-40x+16$$ By Factoring: $$(5x-4)(5x-4)=0$$ Use the Zero-PRoduct Property by equating each unique factor to zero, then solve each equation to obtain: $5x -4 =0$ $5x = 4$ $x=\dfrac{4}{5}$