Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 25


Zeros: $ 2 \sqrt{2},-2 \sqrt{2}$ $x$-intercepts: $ 2 \sqrt{2},-2 \sqrt{2}$

Work Step by Step

To find the zeros of a function $f$, solve the equation $f(x)=0$ The zeros of the function are also the $x-$intercepts. Let $f(x)=0$: $$x^2-8=0$$ Using the Square Root Method $$x^2=8$$ $$ x = \pm \sqrt{8}$$ $\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2 \sqrt{2}$ $$ x = \pm 2 \sqrt{2}$$ $\therefore x = 2 \sqrt{2} \text{ or } x = -2 \sqrt{2}$
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