Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 16


the zeros are $x=-1$ or $x=-6$ and the $x$-intercepts are $(-1,0)$ and $(-6,0)$.

Work Step by Step

By factorization, we have $$ F(x)=x^2+7x+6=(x+1)(x+6) .$$ That is, we have $x+1=0 $ or $x+6=0$. So the zeros are $x=-1$ or $x=-6$ and the $x$-intercepts are $(-1,0)$ and $(-6,0)$.
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