Answer
the zeros are $x=\pm 3$ and the $x$-intercepts are $(\pm3,0)$.
Work Step by Step
By factorization, we have
$$
G(x)=x^2-9=(x-3)(x+3)
.$$
That is, we have $x-3=0 $ or $x+3=0$. So the zeros are $x=\pm 3$ and the $x$-intercepts are $(\pm3,0)$.
