Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 27

Answer

Zeros: $3,-1$ $x$-intercepts: $3,-1$

Work Step by Step

To find the zeros of a function $g$, solve the equation $g(x)=0$ The zeros of the function are also the $x-$intercepts. Let $g(x)=0$: $$(x-1)^2-4=0$$ Using the Square Root Method $$(x-1)^2=4$$ $$ (x-1) = \pm \sqrt{4}$$ $$(x-1) =\pm 2$$ $\therefore x-1 = 2 \text{ or } x-1 = -2 $ $x-1 = 2 \to x = 3$ $x-1 = -2 \to x =-1$
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