Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 92

Answer

$ \frac{-2(x^2-5x-9)}{(x^2+9)^2}$

Work Step by Step

$\frac{(x^2+9)\cdot2-(2x-5)\cdot2x}{(x^2+9)^2}=\frac{2x^2+18-4x^2+10x}{(x^2+9)^2}=\frac{-2x^2+10x+18}{(x^2+9)^2}=\frac{-2(x^2-5x-9)}{(x^2+9)^2}$
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