Answer
$\ \frac{3x+2}{x-1}$
Work Step by Step
$\frac{4(x+2)^{-1}-3}{3(x+2)^{-1}-1}=\frac{4(x+2)^{-1}-3}{3(x+2)^{-1}-1}\times\frac{x+2}{x+2}=\frac{4-3(x+2)}{3-(x+2)}=\frac{-3x-2}{-x+1}=\frac{3x+2}{x-1}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 84
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