Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 61

Answer

$\frac{5x}{(x+4)(x-1)(x-6)}$

Work Step by Step

$\frac{x}{x^2-7x+6}-\frac{x}{x^2-2x-24}=\frac{x}{(x-1)(x-6)}-\frac{x}{(x+4)(x-6)}=\frac{x(x+4)-x(x-1)}{(x+4)(x-1)(x-6)}=\frac{5x}{(x+4)(x-1)(x-6)}$
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