Answer
$\frac{5x}{(x+4)(x-1)(x-6)}$
Work Step by Step
$\frac{x}{x^2-7x+6}-\frac{x}{x^2-2x-24}=\frac{x}{(x-1)(x-6)}-\frac{x}{(x+4)(x-6)}=\frac{x(x+4)-x(x-1)}{(x+4)(x-1)(x-6)}=\frac{5x}{(x+4)(x-1)(x-6)}$
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