Answer
$\frac{-5x+4}{(x+1)(x-2)(x+3)}$
Work Step by Step
$\frac{\frac{x-2}{x+1}-\frac{x}{x-2}}{x+3}=\frac{(x-2)^2-x(x+1)}{(x+1)(x-2)(x+3)}=\frac{-5x+4}{(x+1)(x-2)(x+3)}$
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