Answer
$\frac{3x^2-4x+4}{(x-1)^2}$
Work Step by Step
$\frac{3x}{x-1}-\frac{x-4}{x^2-2x+1}=\frac{3x}{x-1}-\frac{x-4}{(x-1)^2}=\frac{3x(x-1)-x+4}{(x-1)^2}=\frac{3x^2-4x+4}{(x-1)^2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 64
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