Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 90

Answer

$ \frac{x^2(4x-15)}{(2x-5)^2}$

Work Step by Step

$\frac{(2x-5)\cdot3x^2-x^3\cdot2}{(2x-5)^2}=\frac{6x^3-15x^2-2x^3}{(2x-5)^2}=\frac{x^2(4x-15)}{(2x-5)^2}$
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