Answer
$ \frac{x^2-6x+11}{(x+1)^2(x+7)}$
Work Step by Step
$\frac{2x-3}{x^2+8x+7}-\frac{x-2}{(x+1)^2}=\frac{2x-3}{(x+1)(x+7)}-\frac{x-2}{(x+1)^2}=\frac{(2x-3)(x+1)-(x-2)(x+7)}{(x+1)^2(x+7)}=\frac{x^2-6x+11}{(x+1)^2(x+7)}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 68
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