Answer
$ \frac{x^2+7x-1}{(x-3)(x+8)}$
Work Step by Step
$\frac{x}{x-3}-\frac{x+1}{x^2+5x-24}=\frac{x}{x-3}-\frac{x+1}{(x-3)(x+8)}=\frac{x(x+8)-x-1}{(x-3)(x+8)}=\frac{x^2+7x-1}{(x-3)(x+8)}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 62
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