Answer
$ \frac{-2x-h}{x^2(x+h)^2}$
Work Step by Step
$\frac{1}{h}(\frac{1}{(x+h)^2}-\frac{1}{x^2})=\frac{1}{h}(\frac{x^2-(x+h)^2}{x^2(x+h)^2})=\frac{-2x-h}{x^2(x+h)^2}$
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