Answer
$ \frac{3x-1}{2x+1}$
Work Step by Step
$\frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2}=\frac{2(x-1)^{-1}+3}{3(x-1)^{-1}+2}\times\frac{x-1}{x-1}=\frac{2+3(x-1)}{3+2(x-1)}=\frac{3x-1}{2x+1}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 83
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