Answer
$\begin{bmatrix} -22 & -6 \\ 18 & 36 \end{bmatrix}$
Work Step by Step
Since, the dimensions of matrix $C$ is $2 \times 3$ and that of matrix $B$ is $3 \times 2$. Thus, the number of columns of matrix-$C$ will be same as the number of rows of the matrix-$B$. and so we can take their product as $BC$.
$CB=\begin{bmatrix} -5 & 4& 1 \\ 0 & 3 & 6 \end{bmatrix} \begin{bmatrix} 5 & 1 \\ 0 & -2 \\ 3 & 7 \end{bmatrix} \\=\begin{bmatrix} -25 +0 +3 &-5-8+7 \\ 0+0+18 & 0-6+42 \end{bmatrix}\\=\begin{bmatrix} -22 & -6 \\ 18 & 36 \end{bmatrix}$
