Answer
$\left[\begin{array}{ll}
-9 & 3\\
6 & 0 \end{array}\right]$
Work Step by Step
We are given that $B=\left[\begin{array}{ll}
-6 & 2\\
4 & 0\end{array}\right]$
Now, $\dfrac{3}{2}B=\dfrac{3}{2} \left[\begin{array}{ll}
-6 & 2\\
4 & 0\end{array}\right]\\=\left[\begin{array}{ll}
-6 (\dfrac{3}{2})& 2(\dfrac{3}{2})\\
4 (\dfrac{3}{2})& 0(\dfrac{3}{2})\end{array}\right]\\=\left[\begin{array}{ll}
-9 & 3\\
6 & 0 \end{array}\right]$
