Answer
\[\left[ {\begin{array}{*{20}{c}}
3&{ - 6} \\
0&{ - 9/2}
\end{array}} \right]\]
Work Step by Step
\[\begin{gathered}
{\text{Let }}A = \left[ {\begin{array}{*{20}{c}}
{ - 2}&4 \\
0&3
\end{array}} \right] \hfill \\
{\text{Find }} - \frac{3}{2}A \hfill \\
- \frac{3}{2}A = - \frac{3}{2}\left[ {\begin{array}{*{20}{c}}
{ - 2}&4 \\
0&3
\end{array}} \right] \hfill \\
{\text{Use the scalar multiplication}} \hfill \\
- \frac{3}{2}A = \left[ {\begin{array}{*{20}{c}}
{ - \frac{3}{2}\left( { - 2} \right)}&{ - \frac{3}{2}\left( 4 \right)} \\
{ - \frac{3}{2}\left( 0 \right)}&{ - \frac{3}{2}\left( 3 \right)}
\end{array}} \right] \hfill \\
- \frac{3}{2}A = \left[ {\begin{array}{*{20}{c}}
3&{ - 6} \\
0&{ - 9/2}
\end{array}} \right] \hfill \\
\end{gathered} \]
