Answer
$\begin{bmatrix} 23 &-9 \\-6 &-2\\ 33 &1 \end{bmatrix}$
Work Step by Step
Since, the dimensions of matrix $B$ is $3 \times 2$ and that of matrix $A$ is $2 \times 2$. Thus, the number of columns of matrix-$B$ will be same as the number of rows of the matrix-$A$. and so we can take their product as $BA$.
$BA=\begin{bmatrix} 5 & 1 \\ 0 & -2 \\ 3 & 7 \end{bmatrix} \begin{bmatrix} 4 &-2 \\ 3 & 1 \end{bmatrix} \\=\begin{bmatrix} 20+3 &-10+1 \\ -6& -2\\ 33 &1 \end{bmatrix}\\=\begin{bmatrix} 23 &-9 \\-6 &-2\\ 33 &1 \end{bmatrix}$
