Answer
$\begin{bmatrix} 27 \\- 1 \end{bmatrix}$
Work Step by Step
Since, the dimensions of matrix $A$ is $2 \times 3$ and that of matrix $B$ is $3 \times 1$. Thus, the number of columns of matrix-$A$ will be same as the number of rows of the matrix-$B$. and so we can take their product $AB$.
$AB=\begin{bmatrix} -6 & 3 & 5 \\ 2 & 9 & 1\end{bmatrix} \begin{bmatrix} -2 \\ 0 \\ 3 \end{bmatrix} \\=\begin{bmatrix} -6(-2)+(3)(0) +5(3) \\(2)(-2)+(9)(0)+(1)(3) \end{bmatrix}\\=\begin{bmatrix} 12+0+15 \\-4+0+3 \end{bmatrix}\\=\begin{bmatrix} 27 \\- 1 \end{bmatrix}$
