Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.7 Properties of Matrices - 9.7 Exercises - Page 930: 65

Answer

$\begin{bmatrix} 2 & 7 &-4 \end{bmatrix}$

Work Step by Step

Consider $A=\begin{bmatrix} -2 & 4 &1\end{bmatrix} $ and $B=\begin{bmatrix} 3&-2&4 \\2&1&4\\0&-1&4\end{bmatrix} $ Since, the dimensions of matrix $A$ is $1 \times 3$ and that of matrix $B$ is $3 \times 3$. Therefore, the number of columns of matrix-$A$ will be same as the number of rows of the matrix-$B$ and so, we can take their product $AB$. $AB=\begin{bmatrix} -2 & 4 &1\end{bmatrix} \begin{bmatrix} 3&-2&4 \\ 2&1& 0\\0&-1&4\end{bmatrix} \\=\begin{bmatrix} (-6)+8+0 &4+4-1 & (-8) +0+4 \end{bmatrix}\\=\begin{bmatrix} 2 & 7 &-4 \end{bmatrix}$
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