Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.7 Properties of Matrices - 9.7 Exercises - Page 930: 57

Answer

$\begin{bmatrix} -17\\-1\end{bmatrix}$

Work Step by Step

Since, the dimensions of matrix $A$ is $2 \times 3$ and that of matrix $B$ is $3 \times 1$. Thus, the number of columns of matrix-$A$ will be same as the number of rows of the matrix-$B$. and so we can take their product $AB$. $AB=\begin{bmatrix} 3 & -4 &1\\5&0&2\end{bmatrix} \begin{bmatrix} -1 \\4\\2\end{bmatrix} \\=\begin{bmatrix} -3-16+2\\-5+0+4 \end{bmatrix}\\=\begin{bmatrix} -17\\-1\end{bmatrix}$ So, the product of $AB$ is equal to $\begin{bmatrix} -17\\-1\end{bmatrix}$
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