Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.3 Determinant Solution of Linear Systems - 9.3 Exercises - Page 884: 7

Answer

$-31$

Work Step by Step

The determinant $D$ of a $ 2 \times 2$ matrix can be calculated as: $D=\left|\begin{array}{ll} A & B\\C & D \end{array}\right|=AD-BC$ The determinant $D$ of a given $ 2 \times 2$ matrix can be calculated as: $D=\left|\begin{array}{ll} -5 & 9\\ 4 & -1 \end{array}\right|=(-5)(-1)-(9)(4)=5-36=-31$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.