Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.3 Determinant Solution of Linear Systems - 9.3 Exercises - Page 884: 30

Answer

$$0$$

Work Step by Step

$$\eqalign{ & \left| {\matrix{ 5 & { - 3} & 2 \cr { - 5} & 3 & { - 2} \cr 1 & 0 & 1 \cr } } \right| \cr & {\rm{Calculating\, the\, determinant \,by \,expanding \,the \,third \,row}} \cr & \left| {\matrix{ 5 & { - 3} & 2 \cr { - 5} & 3 & { - 2} \cr 1 & 0 & 1 \cr } } \right| = 1\left| {\matrix{ { - 3} & 2 \cr 3 & { - 2} \cr } } \right| - 0\left| {\matrix{ 5 & 2 \cr { - 5} & { - 2} \cr } } \right| + 1\left| {\matrix{ 5 & { - 3} \cr { - 5} & 3 \cr } } \right| \cr & {\rm{Solving}} \cr & \left| {\matrix{ 5 & { - 3} & 2 \cr { - 5} & 3 & { - 2} \cr 1 & 0 & 1 \cr } } \right| = \left( {6 - 6} \right) - 0 + \left( {15 - 15} \right) \cr & {\rm{Simplifying}} \cr & \left| {\matrix{ 5 & { - 3} & 2 \cr { - 5} & 3 & { - 2} \cr 1 & 0 & 1 \cr } } \right| = 0 \cr} $$
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