Answer
$-6$
Work Step by Step
The determinant $D$ of a $ 2 \times 2$ matrix can be calculated as:
$D=\left|\begin{array}{ll}
A & B\\C & D \end{array}\right|=AD-BC$
The determinant $D$ of a given $ 2 \times 2$ matrix can be calculated as:
$D=\left|\begin{array}{ll}
6 &-4\\ 0 & -1 \end{array}\right|=(6)(-1)-(-4)(0)=-6+0=-6$
