Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 9 - Systems and Matrices - 9.3 Determinant Solution of Linear Systems - 9.3 Exercises - Page 884: 26

Answer

$$ - 71$$

Work Step by Step

$$\eqalign{ & \left| {\matrix{ 7 & { - 1} & 1 \cr 1 & { - 7} & 2 \cr { - 2} & 1 & 1 \cr } } \right| \cr & {\rm{Calculating\, the\, determinant\, by \,expanding\, the\, third\, column}} \cr & \left| {\matrix{ 7 & { - 1} & 1 \cr 1 & { - 7} & 2 \cr { - 2} & 1 & 1 \cr } } \right| = 1\left| {\matrix{ 1 & { - 7} \cr { - 2} & 1 \cr } } \right| - 2\left| {\matrix{ 7 & { - 1} \cr { - 2} & 1 \cr } } \right| + 1\left| {\matrix{ 7 & { - 1} \cr 1 & { - 7} \cr } } \right| \cr & {\rm{Solving}} \cr & \left| {\matrix{ 7 & { - 1} & 1 \cr 1 & { - 7} & 2 \cr { - 2} & 1 & 1 \cr } } \right| = \left( {1 - 14} \right) - 2\left( {7 - 2} \right) + 1\left( { - 49 + 1} \right) \cr & {\rm{Simplifying}} \cr & \left| {\matrix{ 7 & { - 1} & 1 \cr 1 & { - 7} & 2 \cr { - 2} & 1 & 1 \cr } } \right| = - 71 \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.