Answer
$(3-i)(3+i)(2-6i)=20-60i$
Work Step by Step
$(3-i)(3+i)(2-6i)$
Begin by evaluating the product between the first two factors. The product of the first two factors represents the factored form of a difference of two squares.
$(3-i)(3+i)(2-6i)=(9-i^{2})(2-6i)=...$
Substitute $i^{2}$ by $-1$ and simplify the first factor:
$...=[9-(-1)](2-6i)=(9+1)(2-6i)=10(2-6i)$
Evaluate the remaining product:
$...=20-60i$
