## Precalculus (6th Edition)

$\color{blue}{-3-i\sqrt{6}}$
Simplify $\sqrt{-24}$ to obtain: $=\sqrt{4(-1)(6)} \\=\sqrt{2^2(-1)(6)} \\=2\sqrt{-1)(6)}$ Since $\sqrt{-1} = i$, the expression above simplifies to: $=2i\sqrt{6}$ Thus, the given expression is equivalent to: $=\dfrac{-6-2i\sqrt{6}}{2}$ Divide each term of the numerator by the denominator to obtain: $=\dfrac{-6}{2} - \dfrac{2i\sqrt{6}}{2} \\=\color{blue}{-3-i\sqrt{6}}$