## Precalculus (6th Edition)

$-i\sqrt{2}-2-(6-4i\sqrt{2})-(5-i\sqrt{2})=-13+4i\sqrt{2}$
$-i\sqrt{2}-2-(6-4i\sqrt{2})-(5-i\sqrt{2})$ Remove all grouping symbols: $-i\sqrt{2}-2-(6-4i\sqrt{2})-(5-i\sqrt{2})=...$ $...=-i\sqrt{2}-2-6+4i\sqrt{2}-5+i\sqrt{2}=...$ Group like terms (real terms together and imaginary terms together): $...=(-2-6-5)+(-i\sqrt{2}+4i\sqrt{2}+i\sqrt{2})=...$ Evaluate the indicated operations and simplify: $...=-13+4i\sqrt{2}$