Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 112: 59

Answer

$ 5 - 12i$

Work Step by Step

$(3-2i)^2 = 3^2 - 6\times 6 \times i + (2i)^2 = 9 - 12i + 4(-1) = 5 - 12i$
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