#### Answer

$ i \sqrt 3$

#### Work Step by Step

$\frac{\sqrt {-24}}{\sqrt {8}} = \sqrt {\frac{-24}{8}} = \sqrt {-3} = \sqrt {-1\times3} = i \sqrt 3$

Published by
Pearson

ISBN 10:
013421742X

ISBN 13:
978-0-13421-742-0

$ i \sqrt 3$

$\frac{\sqrt {-24}}{\sqrt {8}} = \sqrt {\frac{-24}{8}} = \sqrt {-3} = \sqrt {-1\times3} = i \sqrt 3$

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