Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 112: 35

Answer

$ i \sqrt 3$

Work Step by Step

$\frac{\sqrt {-24}}{\sqrt {8}} = \sqrt {\frac{-24}{8}} = \sqrt {-3} = \sqrt {-1\times3} = i \sqrt 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.