#### Answer

$(-4-i)-(2+3i)+(-4+5i)=-10+i$

#### Work Step by Step

$(-4-i)-(2+3i)+(-4+5i)$
Remove all grouping symbols:
$(-4-i)-(2+3i)+(-4+5i)=-4-i-2-3i-4+5i=...$
Group like terms (real parts together and imaginary parts too):
$...=(-4-2-4)+(-i-3i+5i)=...$
Evaluate the indicated operations:
$...=-10+i$