Precalculus (6th Edition)

$(-4-i)-(2+3i)+(-4+5i)=-10+i$
$(-4-i)-(2+3i)+(-4+5i)$ Remove all grouping symbols: $(-4-i)-(2+3i)+(-4+5i)=-4-i-2-3i-4+5i=...$ Group like terms (real parts together and imaginary parts too): $...=(-4-2-4)+(-i-3i+5i)=...$ Evaluate the indicated operations: $...=-10+i$