Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 112: 55



Work Step by Step

$(2+i)(3-2i)$ Evaluate the product by multiplying each term of the first factor by every term of the second factor: $(2+i)(3-2i)=6-4i+3i-2i^{2}=...$ Substitute $i^{2}$ by $-1$ and simplify: $...=6-4i+3i-2(-1)=6-i+2=8-i$
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