Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.3 Complex Numbers - 1.3 Exercises - Page 112: 38

Answer

$$\frac{1}{3}$$

Work Step by Step

$\frac{\sqrt{-8}}{\sqrt{-72}}=\frac{i\sqrt{8}}{i\sqrt{72}}$ $(\frac{i}{i})(\sqrt {\frac{8}{72}})$ $\sqrt{\frac{1}{9}}$ $$\frac{1}{3}$$
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